4(x)^2-34(x)+42=0

Solution for 4(x)^2-34(x)+42=0 equation:

4(x)^2-34(x)+42=0

a = 4; b = -34; c = +42;
Δ = b2-4ac
Δ = -342-4·4·42
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-22}{2*4}=\frac{12}{8}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+22}{2*4}=\frac{56}{8}
=7
$